Kablo / Hat Güç Kaybı (I²R) Nasıl Hesaplanır?
conductive power loss P = n·I²·R It is found with; resistance R = ρ·L/A‘(n=3 in three-phase, n=2 in single-phase). For example, in a 3-phase, 100 A, 120 m, 35 mm² copper line, R ≈ 0.061 Ω and loss ≈ 1.831 W; this means an energy loss of ≈ 7.323 kWh in 4,000 hours of operation per year.
R = ρ·L/A · 3F loss = 3·I²·R · 1F loss = 2·I²·R
Example calculation: 3-phase 100 A, 120 m, 35 mm² copper → R ≈ 0.061 Ω, loss = 3×100²×0.061 ≈ 1.831 W; ≈ 7.323 kWh with 4.000 hours/year.
Cable/Line Power Loss (I²R)
Calculate the conductor power loss (I²R) in a transmission/distribution line; you can also see the annual energy loss and cost if desired.
Conductor resistance R
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Power loss
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Annual energy loss
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Notes: R = ρ·L/A · 3F loss = 3·I²·R, 1F loss = 2·I²·R (round trip). ρ: copper 0.0178, aluminum 0.0284 Ω·mm²/m (20 °C). It is an omics approach; The increase in resistance with temperature and harmonic effects are neglected. The loss is reduced by increasing the cross-sectional area or by correcting the power factor.
How is it calculated?
- Enter the system (1F/3F) and line current (A).
- Select the line length (m), cross-section (mm²), and conductor material.
- (Optional) Enter the annual working hours and rate and click Calculate.
Frequently Asked Questions
How is cable power loss calculated?
In a three-phase line, P = 3·I²·R; conductor resistance R = ρ·L/A (ρ: copper 0.0178, aluminum 0.0284 Ω·mm²/m).
How to reduce line loss?
This is reduced by increasing the cable cross-section, shortening the line, or improving the power factor (reducing the current).
Does the loss calculation include heat?
This device uses an ohmic resistance of 20°C; as the conductor heats up, the resistance, and therefore the loss, increases somewhat.
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